Finish Line Great Northern, Operations Management Exam 2: Chapter 8 (True or False). About featured snippets•FeedbackQuestions & answersQuizletQuestionIn assembly-line balancing, the theoretical minimum number of workstations is found by a ratio of the sum of all task times divided by the cAnswer · 0 votesTrueMoreQuizletQuestion. In assembly-line balancing the theoretical minimum number of workstations is found by a ratio of the sum of all task times divided by the cycle time.Answer · 0 votesTrueMoreCheggQuestionUsing the assembly-line balancing procedures for anyassembly-line balancing problem, which of the following is mostcorrect?Multiple ChoiceA. The theoretical minimum number of workstations is always lessthan or equal to number of workstations actually used.B. The theoretical minimum number of workstations is never lessthan number of workstationsAnswer · 21 votesAnswer - A. The theoretical minimum number of workstations is always less than or equal to theMoreCheggQuestionIn assembly-line balancing, the theoretical minimum number of workstations is: A. not always possible to achieve when tasks are actually assigned to stations: B. always (When a fraction) rounded upward to the next larger integer value C. the ratio of the sum of ail task times to cycle time D. the ratio of the sum of all task times to cycle time and alwaysAnswer · 0 votesThe correct answer is:MoreBrainly.comQuestionin assembly-line balancing, the theoretical minimum number of workstations is:Answer · 0 votesThe theoretical minimum number of workstations in assembly-line balancing is determined by the formula: (N_t = lceil frac{N}{U}ceil)where (N_t) is the theoretical minimum number of workstations, (N) is the total number of tasks, and (U) is the cycle time.To calculate the theoretical minimum number of workstations in assembly-line balancing, we use the formula mentioned above. The formula divides the total number of tasks by the cycle time and then rounds up to the nearest whole number. The rationale behind this calculation is to ensure that each workstation can complete its assigned tasks within the specified cycle time.The numerator, (N), represents the total number of tasks required to complete the assembly process. The denominator, (U), represents the cycle time, which is the time allocated to each workstation for completing its tasks.By dividing the total number of tasks by the cycle time and rounding up, we obtain the minimum number of workstations required to compl…MoreBartlebyQuestion7. Using the assembly-line balancing procedures for any assembly-line balancing problem, which of the following is most correct? Multiple Choice The theoretical minimum number of workstations is always less than number of workstations actually used. The theoretical minimum number of workstations is sometimes more than number of workstations actually used. The theoretical minimum number of workstations is sometimes less than Y and sometimes more than number of workstations actually used. The theoretical minimum number of workstations is always less than or equal to number of workstations actually used. The theoretical minimum number of workstations is never less than number of workstations actually used.Answer · 0 votesStep 1 Assembly line balancing is a production strategy that helps in setting an intended rate of production for producing a particular product within a specific time frame.Assembly line balancing refers to the assignment of ne.MoreCliffsNotesQuestionplease help with question below: . Balance the assembly line.Answer · 0 votesGood day Student,Please see the answers and solutions below:Answers & Solutions:(a)Output = 60pcsOperation time = 8hrs = 8*60minsCycle time = Operation time per day / output per day = (8*60)/ 60 = 8minsTheoretical minimum number of workstations required = sum of total task times/ cycle time= (4 + 3 + 2 + 4 + 1 + 4 + 1 + 4 + 2 + 1 + 2 ) / 8 = 3.5 or 4Theoretical minimum number of workstations required = 4WorkstationTasksTotal TimeIdle Time (Cycle time - Total Time)1A, B, E802D, G, H713I, J, K714C, F62Total284Efficiency = sum of all task time / (actual number of workstation * cycle time) = (4 + 3 + 2 + 4 + 1 + 4 + 1 + 4 + 2 + 1 + 2 ) / (4*8)Efficiency = 0.875 ~ 87.5%(b)Output = 48 pcsOperation time = 8hrs = 8*60minsCycle time = Operation time per day/ output per day = (8*60)/ 48 = 10minsTheoretical minimum number of workstations required = sum of total task / cycle time= (4 + 3 + 2 + 4 + 1 + 4 + 1 + 4 + 2 + 1 + 2 )/ 10 = 2.8 …MoreNumeradeQuestionText: Chapter 2 - Line Balancing ExerciseThe table below defines the precedence relationships and element times for a new assembled product:(a) Construct the precedence diagram for this job.(b) Assuming that the cycle time is 11 minutes, what is the theoretical minimum number of workstations or workers assuming one worker per station?(c) Using the largest candidate rule, assign work elements to stations assuming CT = Min.(d) Solve the problem using the Kilbridge and Wester method assuming CT = 1 minute.(e) Solve the problem using the ranked positional weights method assuming CI = Min.(f) Determine the efficiency of the line balance for parts and work elements.Work element (run)Immediate predecessorsWork element time (min)Immediate predecessorsAnswer · 2 votesHi we'll be doing the line balancing solution using the largest candidate rule, so using the largest candidate rule we'll be having so we'll start with the the the table. So the table we have drawn here is this, so that will give the list of the elements by value and the location of elements to the different stations. So the elements, the he de element and the time is given here and he and the state the conditions. The stations and the elements- these are the values and t and s. These are the values, so here the next part we have the balance delay, so the balance 0 would be balance. Delay is basically equal to 5. Times is 5 times, 1 minus 443 whole divided by 5 times 1 comma 0. So this comes out to be in the percentage form there in the fraction form the decimal form. It is 0.14, but if you want to write that in the percentage from multiplied that with 100, that will give us 14 percent. So that is the balance delay, which is dis, quadrant percent by using the the largest cand. Thank yo…MoreCourse HeroQuestion(1) Develop a solution for the following line balancing problem.Answer · 0 votesThe step by step solution of the same is as follows: Image transcriptions The Precedence Diagram as follows: Total duration of all tasks together [ A to G} =70+60+120+60+240+100+190 = 840 seconds Required cycle time = 5 minutes = 300 seconds Therefore . Theoretical minimum number of workstations = Total duration of all tasks I Cycle time = 840.!“ 300 = 18 [3 rounded to nearest whole number} THEORETICAL MINIMUM NUMBER OF WORKSTATIONS = 3 The line is being balanced as per following in such a way so that total duration of tasks in any workstation shall not exceed required cycle time of 300 seconds : WORKSTATION TASKS DURATION [SECS] IDLE TIME = 300 SECS - DURATION 70 + 60+ 120 + 250 300 — 250 = 50 60 + 240 = 300 100 + 190 = 290 300 — 290 = 10 As. per above arrangement , the solution achieves minimum number of stations of 3 Total idle time for 3 workstations together 2 50 + D + 10 seconds = 60 seconds Efficiency of this line = [ Total duration of tasks I I i 3 x Cycle time i x 100 = 34m [ …MoreTranstutorsQuestionDraw the network ? Calculate theoretical minimum number of workstations? Balance the line by assi.Answer · 12 votesFind.MoreQuiz+QuestionA manufacturing cell layout is similar to the workcenter and assembly-line layouts.Answer · 1 voteThe Answer is: TrueExplanation: A manufacturing cell groups dissimilar machines to work on products that have similar shapes and processing requirements.A manufacturing cell is similar to a workcenter in that cells are designed to perform a specific set of processes, and it is similar to an assembly line in that the cells are dedicated to a limited range of products.More Feedback Finish Line Greenspoint, Solved Using the assembly-line balancing procedures for. A. The theoretical minimum number of workstations is always less than or equal to number of workstations actually used. B. The theoretical minimum number of .1 answer  ·  Top answer: Answer - A. The theoretical minimum number of workstations is always less than or equal to the Finish Line Grove City, In Assembly Line Balancing The Theoretical Minimum .. Jun 23, 2023 — Question: A workcenter is a basic production layout format in which similar equipment or functions are grouped together. Answer: True. Finish Line Hattiesburg Ms, Chapter 08 Test Bank version1.docx - Student name. 11)In assembly-line balancing, the theoretical minimumnumber of workstations is found by a ratio of the sum of alltask times divided by thecycle time. Rating: 5 · ‎1 review Finish Line Ingram, Assembly Line Balancing: Workstations - YouTube. 10:55Assembly Line Balancing: Workstations. 69K views · 9 years ago .more. Cary Countryman. 2.2K. Subscribe. 2.2K subscribers. 259. Share. Save.YouTube · Cary Countryman · Nov 7, 201310 key moments in this video Finish Line Lacrosse, IE 314: Operations Management II. PDFAssembly-Line Balancing . Balance the line. . What is the theoretical minimum number of workstations needed to meet the schedule? e. Balance this line .11 pages Longchamp San Francisco, Page 1. 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